Question
Find the area of triangle having sides 8 m, 9 m, and 13
Find the area of triangle having sides 8 m, 9 m, and 13
m.
Here s = semi perimeter = (8 + 9 + 13)/2 = 15 m So area of this triangle = √(15 (15 - 8)(15 - 9)(15 - 13)) = √(15 × 7 × 6 × 2) = 6√35 m 2 More Geometry Questions
- In the given figure. ABCDEF is a regular hexagon whose side is 6 cm. APF, QAB, DCR and DES are equilateral triangles. What is the area (in cm2) of the shad...
- In the given Figure, Find angle BCD. If AB is a diameter & AB is parallel to CD.
- The length of the each side of an equilateral triangle is 28√3. The area of incircle, (cm 2 ) is
- If in a ΔABC, AD is internal angle bisector & D is a point on BC, AB = 8 cm, BC = 10 cm then what is BD:CD?
- Question 5
- Length of a chord in a circle of radius 'r' cm, is 14 cm and distance between chord and centre of the circle is 24 cm. Find the value of (4r - 60).
- The 2nd approximation to a root of the equation x2-x-1-0 in the interval (1, 2) by Bisection method will be:
- In a triangle, the three interior angles are in the ratio 3 : 4 : 5. What is the measure of the largest angle?
- The length of the each side of an equilateral triangle is 42√3 cm . The area of circumcircle, (cm 2 ) is
- If G is the centroid and AD, BE, CF are three medians of ∆ABC with area 78 cm 2 , then the area of ∆BGF is?
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)