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    Question

    Find the area of triangle having sides 9 m, 40 m, and 41

    m.
    A 630 cm² Correct Answer Incorrect Answer
    B 330 cm² Correct Answer Incorrect Answer
    C 546 cm² Correct Answer Incorrect Answer
    D 180 cm² Correct Answer Incorrect Answer

    Solution

    As sides 9, 40 & 41 is a Pythagoras triplet means 92 + 402 = 412 ; this is a right angle triangle. So area of this triangle = 1/2 × base × height = (1/2) × 9 × 40 = 180 cm 2

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