∆ABC and ∆DEF are similar and their areas are respectively 16 cm2 and 64 cm 2 . If EF = 6 cm BC is?
Ratio of perimeter of similar triangles = ratio of the corresponding sides of similar triangles. (area of ∆ABC)/(area of ∆DEF)=(BC/EF) 2 16/64 = (BC/6) 2 (4/8) 2 = (BC/6) 2 4/8 = BC/6 BC = (4 × 6)/8 = 3 cm
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