According to the question, AB.BC = (1 )/(2 ) AC² 2AB. BC = AB² + BC² AB² + BC² - 2 AB.BC = 0 (AB – BC)² = 0 AB = BC , ∠ ACB = ∠ CAB = 45⁰
7(3/6) of 534 + 262 = 61800 - ?
(12% of 1250 + 85% of 400) x 10 = ?2
(112 × 4) ÷ 16 + 484 = (?)3
[∛(3375/19683 )- ∛(125/1728 ) ] ÷ ∛(64/729) = ? - 3/8
35 × 540 ÷ 18 of 15 – ? = 15
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
15.8% of 9000 + 20.4% of 7500 = 30% of ?
(√1024 + √324)% of 780 = ?% of 260