In a right angle triangle, the product of two sides is half of the square of the third side (i.e., hypotenuse). Accordingly find out the acute angle?
According to the question, AB.BC = (1 )/(2 ) AC² 2AB. BC = AB² + BC² AB² + BC² - 2 AB.BC = 0 (AB – BC)² = 0 AB = BC , ∠ ACB = ∠ CAB = 45⁰
