Question

    The greatest number of four digits which when divided by

    5, 8, 11 leave remainders 2, 4, 6 respectively is:
    A 9677 Correct Answer Incorrect Answer
    B 9700 Correct Answer Incorrect Answer
    C 9983 Correct Answer Incorrect Answer
    D 9897 Correct Answer Incorrect Answer

    Solution

    The difference between divisor and the corresponding remainder is equal (i.e 3). LCM of 5, 8 and 11 = 440 Largest 4-digit number = 9999 After dividing 9999 by 440 we will get the remainder as 319. Therefore, the number divisible by 440 = 9999 – 319 = 9680 If 3 is subtracted from the number 9680 the resulting number will follow the condition in the question and that number is 9677.

    Practice Next