Question
Two numbers are in the ratio 2:8. The product of their
H.C.F. and L.C.M. is 3600. The sum of the numbers is:Solution
Let the numbers be 2x and 8x respectively. First number × second number = HCF × LCM => 2x × 8x = 3600 => x2 = [3600/(2×8)] = 225 => x = √225 = 15 Sum of the numbers = 2x + 8x = 10x = 10 × 15 = 150
Suresh earned an interest of Rs. 1677 on principal amount of Rs. 5200 at some rate of compound interest in 2 years. How much more/less interest would he...
A sum fetched a simple interest of ₹3,040 at the rate of 8 %.p.a. in 5 years. What is the sum?
The difference between the compound interest, compounded annually and simple interest on Rs. ‘P’ at the rate of 20% p.a. for 2 years, is Rs....
An amount of Rs. 'x' is invested at a simple interest rate of 15% per annum and grows to Rs. 14,500 after 3 years. If the same am...
Two persons A and B invest money in two schemes. A invests Rs. 6000 for 2 years in R% CI per annum. B invests Rs.7000 for 2 years in 20% CI per annum. I...
- Rs. 3,000 becomes Rs. 4,200 in 10 years at simple interest of r% p.a. If Rs. 6,000 is invested at 0.5r% p.a. for 6 years, what will be the interest amount?
Rohit invested a sum on compound interest at 'R%' per annum (compounded annually), which amounts to ₹8,000 and ₹11,520 in 2 years and 4 years respec...
An investment of ₹15,000 is made for 4 years at an annual compound interest rate of 6%. After 2 years, ₹5,000 is withdrawn. Calculate the approxima...
A man deposited Rs. ‘x + 1400’ at 12% per annum simple interest and earned Rs. 828 as interest after 2 years. Find the interest earned by him if he ...
The interest received by investing Rs. 2900 for 2 years at compound interest of 20% p.a., compounded annually, was re-invested for 3 years at simple int...
Relevant for Exams:
