Question
Two numbers are in the ratio 4:7. The product of their
H.C.F. and L.C.M. is 5488. The sum of the numbers is:Solution
Let the numbers be 4x and 7x respectively. First number × second number = HCF × LCM => 4x × 7x = 5488 => x2 = [5488/(4×7)] = 196 => x = √196 = 14 Sum of the numbers = 4x + 7x = 11x = 11 × 14 = 154
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