Question
Find the least number which when divided separately by
15, 20, 35 and 45 leaves 3 as remainder in each case?Solution
LCM of 15, 20, 35, 45 = 1260 The LCM is exactly divisible by all the four ∴ Required number = 1260 + 3 = 1263
More HCF and LCM Questions
2 3 4 15 56 ?
...-3 -10 -40 -185 -905 -4500
-4 a b c d e
Find the value of d.
...11Â Â Â 12.1Â Â Â Â 14.3Â Â Â Â 17.6Â Â Â Â Â 22Â Â Â Â Â ?
21, 37, 62, 98, 147, ?
12, 6, 6, 9, 18, ?
5Â Â Â Â 13Â Â Â Â 36Â Â Â Â 145Â Â Â Â Â 719Â Â Â Â 4321
3 4.5 6.75 10.125 15.1875 22.78125 ?
...504 625 769 938 1134 ?
...Select the number from among the given options that can replace the question mark (?) in the following series.
64, 60, 52, 40, ?, 4
If 24 33 x 42 6 51
Then, 20% of x + 40% of x=?
...
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