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Distance = 20 km Speed of A = 4 km per hour Speed of B = 2 km per hour Speed of C = 10 km per hour Time = Distance/speed Time taken by A = 20/4 hours = 5 hours Time taken by B = 20/2 hours = 10 hours Time taken by C = 20/10 hours = 2 hours The required time = LCM of 5, 10, 2 = 10 ∴ All three will meet again at starting point after 10 hours
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The value of tan2 θ + cot2 θ − sec2 θ cosec2 θ is:
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The radius of a hemisphere is 10 cm. What is the total surface area of the hemisphere (including the base)?
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