Distance = 20 km Speed of A = 4 km per hour Speed of B = 2 km per hour Speed of C = 10 km per hour Time = Distance/speed Time taken by A = 20/4 hours = 5 hours Time taken by B = 20/2 hours = 10 hours Time taken by C = 20/10 hours = 2 hours The required time = LCM of 5, 10, 2 = 10 ∴ All three will meet again at starting point after 10 hours
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Attributes that do not exist in the physical database, but their values are derived from other attributes present in the database.
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In a compiler, keywords of a language are recognized during
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Sending a packet to all destination simultaneously is called
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