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    Question

    Find out the sum of digits of largest number that leaves

    same remainder when it divides 12003, 6006, 5506 and 10006. 
    A 5 Correct Answer Incorrect Answer
    B 4 Correct Answer Incorrect Answer
    C 3 Correct Answer Incorrect Answer
    D 2 Correct Answer Incorrect Answer

    Solution

    To leave same remainder the difference between two dividends must be divisible by the divisor Taking difference of the numbers in descending order ⇒ 12006 – 11006 = 1000 ⇒ 11006 – 6006 = 5000 ⇒ 6006 – 5506 = 500 Each interval must be divisible by the divisor. ⇒ We need HCF of these numbers 1000, 5000 and 500 is 500 ∴ sum of digits = 5 + 0 + 0 = 5

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