Question
The L.C.M of a² – 2a – 3 and a³ + a² + a + 1
isÂSolution
Consider, the first expression a2 - ax - 3 Find the factors of first expression ⇒ a2 – 2a - 3 = (a - 3)(a + 1) Now, consider, the second expression a3 + a2 + a + 1 Find the factors of the second expression ⇒ a3 + a2 + a + 1 = a2 (a + 1) + (a + 1) ⇒ a3 + a2 + a + 1 = (a2 + 1)(a + 1) The common factors of the two expressions a2 – 2a - 3 and a3 + a2 + a + 1 is (a + 1) (a - 3) is extra factor in the first expression and (a2 + 1) are the extra factor in the second expression. Therefore, the required L.C.M. of a2 – 2a – 3 and a3 + a2 + a + 1 is (a + 1)(a - 3)(a2 + 1).
- The base of a right pyramid is an equilateral triangle with side 12 cm. If the height of the pyramid is 40√3 cm, calculate the volume of the pyramid.
In triangle ABC, the difference between angle A and angle B is 16°, and the difference between angle A and angle C is 8°. Determine the measure of an...
If area of similar triangles ∆ ABC and ∆ DEF be 64 sq Cm and 121 sq cm and EF = 15.4 cm then BC equals
Find the length of AB, if ΔABC ~ ΔRQP and AC = 22.5 cm, RP = 9 cm and RQ = 6 cm.
The angles of a triangle are in the ratio 4:5:3. Determine the sum of the smallest and largest angles of the triangle.
If the angles of a triangle are in the ratio of 2:5:8, then find the value of the biggest angle.
Find the area of a triangle whose sides are 12 m, 14 m, and 16 m.
In a right-angled triangle, the legs are in the ratio 3:4, and the hypotenuse is 25 cm. Find the perimeter of the triangle.
- A triangle has a base of 27.3 cm and the height is 11.4 cm. Find its area.
ABC is an equilateral triangle with sides of 24cm. Find the difference between its in-radius and circum-radius.