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ATQ, Let HCF of two numbers be ‘x’ So, LCM of two numbers = 18 × x = 18x Or, x × 18x = 64800 Or, 18x² = 64800 Or, x² = 3600 Or, x = √3600 = 60 LCM of two numbers = 60 × 18 = 1080 Let two numbers be ‘60a’ and ‘60b’, where ‘a’ and ‘b’ are co-prime numbers. So, 60ab = 1080 Or, a × b = 18 So, when a = 1 and b = 18, then difference will be maximum Desired difference = 60 × 18 – 60 × 1 = 1020
139.88% of 119.89 + 1451.89 ÷ 6.01 - √196.01 = ? ÷ 3.01 + 215.98
(4913)1/3 × 10.11 × 13.97 ÷ 20.32 = ? + 39.022
?² × 55% of (29 + 32 - 41) = 41.66% of 216 + 9
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
19.99% of 79.98 = ?2– 159.99% of 12.5
(44/25) ÷ (154/199.5) × 419.91 = ? – (11.11)3
24.035 × √? = 4607.89 ÷ 11.8259
?% of 399.97 = 11.982 + 16.13 × 4.16 – 35.99