Find the value of a such that (x + a) is the H.C.F of the polynomials 3x²-2x - 8 and 2x²- 7x -6.
3x²-2x - 8 3x²-6x+4x–8 3x(x-2) +4(x-2) (3x+4) (x-2) … (1) 2x²- 7x -6 2x²-4x-3x+6 2x(x-2)-3(x-2) (2x-3) (x-2) … (2) HCF of Equation (1) and (2). HCF=x-2 ATQ- X+ a =x-2 a =-2.
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