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    Question

    The highest common factor (HCF)

    of two numbers is 17. If their product is 867, how many pairs of numbers satisfy these conditions?
    A 1 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 5 Correct Answer Incorrect Answer
    D 8 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the two numbers be '17x' and '17y', where 'x' and 'y' are co-prime. ATQ; 17x × 17y = 867 So, xy = 3 Since, '3' is a prime number, ab = 3 × 1 or 1 × 3, Either way, only one pair exists. 

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