Question
What is the least number that should be multiplied to
735 so that it becomes divisible by 42?Solution
Since, 735 = 3 Γ 5 Γ 7 Γ 7 To be divisible by β42β, a number must be divisible by all 2, 3 and 7. Since, 735 is divisible by β3β and β7β. So, the least number that we need to multiply is β2β. Therefore, required answer is 2.
The HCF and LCM of two consecutive even number is 2 and 112 respectively. Find the sum of reciprocal of these two numbers?
The least number which when divided by 4, 8, 10 and 12 leave zero remainder in each case and when divided by 13 leaves a remainder of 9 is:
The L.C.M of aΒ² β 2a β 3 and aΒ³ + aΒ² + a + 1 isΒ
Find the greatest number that will divide 550, 675 and 500 without leaving a remainder.
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HCF of two numbers 50 and 80 can be expressed in the form of (30m β 110) whereas LCM of these two numbers can be expressed in the form of (60n β 20)...
If total number of factors of 5,292 is 'x', then find the value of (x - 7)(x + 2).
The least number which when divided by 4, 6, 10 and 12 leave zero remainder in each case and when divided by 13 leaves a remainder of 8 is:
If the total number of factors of 1250 is 'y', then find the value of (y - 4)(y + 7).
Three numbers are in the ratio 2:3:6 respectively. If the HCF of the numbers is 5, then find the LCM of the numbers.