Question
Determine the total count of prime factors in the
product: 217Â x 197Â x 107Solution
For a number (N) whose prime factorization is of the form, N = ap X bq X cr, where 'a', 'b' and 'c' are prime numbers, then total number of prime factors of the number 'N' will be = (p + q + r)
Given expression: 217Â X 197Â X 107Â = 37Â X 77Â X 197Â X 27Â X 57
Therefore, total number of prime factors = (7 + 7 + 7 + 7 + 7) = 35
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