Get Started with ixamBee
Start learning 50% faster. Sign in now
Get Started with ixamBee
Start learning 50% faster. Sign in nowAs HCF is 13 so let numbers be 13x & 13y. It means x & y must be co-prime. Now 13x+ 13y = 65, So x + y = 5. Now pairs of (x , y) can be (1,4) , (2,3) and all are co-prime so number of pairs are 2.
(129.98% of 8460) + (119.899% of 8640) = (130.009% of 15820) + ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
30.02% of 420.11 + 44.96% of 499.96 - 203.12 = ?
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...30.22% of (79.9 x 6.01) + 69.97 =?
14.2% of 7200 + 2.8% of 6400 =?
? = 460.24 + 1057.97 – 14.992
499.98% of (√440.8 + 12.922 ) - 12.02 of 4.82 = ? of 9.82 + 9.98% of 999.94
