The sum of two numbers is 126 and their HCF is 14. Total number of such pairs of numbers is?
As HCF is 14 so let numbers be 14x & 14y. It means x & y must be co-prime. Now 14x+ 14y = 126, So x + y = 9. Now pairs of (x , y) can be (1,8) , (2,7) , (3, 6) & (4,5) but (3,6) is not co-prime hence number of pairs are 3.
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