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    Question

    data-sheets-value="{"1":2,"2":"The product of two numbers is 10140 and their HCF is 13. Total number of such pairs of numbers is "}" data-sheets-userformat="{"2":4993,"3":{"1":0},"10":2,"11":4,"12":0,"15":"arial,sans,sans-serif"}">The product of two numbers is 10140 and their HCF is 13. Total number of such pairs of numbers is?
    A 2 Correct Answer Incorrect Answer
    B 4 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 5 Correct Answer Incorrect Answer

    Solution

    As HCF is 13 so let numbers be 13x & 13y. It means x & y must be co-prime. Now 13x × 13y = 10140, So xy = 60. Now pairs of (x, y) can be (1,60) , (2,30) , (3,20) , (4,15) , (5,12) & (6, 10). Here only (1,60) , (3,20) , (4,15) & (5, 12) are co-prime so number of pairs are 4.

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