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As HCF is 9 so let numbers be 9x & 9y. It means x & y must be co-prime. Now 9x × 9y = 972, So xy = 12. Now pairs of (x, y) can be (1,12) , (2,6) & (3,4). Here only (1,12) & (3,4) are co-prime so number of pairs are 2.
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