Find the least number of four digits which is exactly divisible by 6, 24 and 32?
Least four digit number = 1000 So when 1000 is divided by LCM of 6,24 & 32 (i.e.96), remainder is 40. So when gap of divisor & remainder is added to 1000, it will be completely divided by 96 & answer will be = 1000 + (96-40) = 1000 + 56 = 1056.
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