The distance between two parallel poles is 65√3m. The angle of depression of the top of the second pole when seen from the top of first pole is 30°. What will be the height of second pole if the first pole is 110 m long?
Let y be the height of second pole In△ AED, Tan 30°= AE/DE 1/√3 = x/65√3 x = (65√3)/√3 x = 65 therefore, height of the second pole = CD = EB = y y = AB - AE y = 110 – 65 = 45 m
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