Question
The height of a conical tent is 9m. A vertical pole of
6m height is placed 4 m away from its centre such that it touches the surface. Find the slant height of the tent from the base to the point where the pole touches it?Solution
Since, triangle’s are similar, AD/AB = DE/BC 3/9 = 4/BC BC = 12m In â–³ ABC, AC = √(AB2 + BC2)) = √(92 + 122) = √(81+144) = √225 = 15 m In â–³ ADE, AE = √(AD2 + DE2) = √(32 + 42) = √(9+16) = √25 = 5 m i.e., CE = AC – AE = 15 – 5 = 10 m
More Height and Distance Questions
5/2 of 5/6 of 12/5 of 54 % of 5250 = ?
?% of (√196) × 24 + 344 = 428
961 × 4 ÷ 31 – 15% of 180 = ? – 73
(75 + 0.25 × 10) × 4 = ?2 - 14
(64/25)? × (125/512)?-1 = 5/8
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
What will come in the place of question mark (?) in the given expression?
34 X 11 - ? + 36 = 3 X 75 + 125
√256 × 25 – 15 × 14 =?
Find the simplified value of the given expression.
18 ÷ 3 + {(48 ÷ 6) of 12} + 10 - 8 of 9
- What will come in place of (?), in the given expression.
(28 × 4) + (96 ÷ 4) – 25 = ?
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