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Apply tan
in ∆BCD Tan
= x / K k = (x / tan
) ---- (1) apply tanβ in ∆ACD => tanβ = (ĥ+x) / K => K = (h + x) / (tanβ) ----- (2) Example like (1) and (2) => x / tan
= (h+x) / tanβ => xtanβ = tan
h + xtan
=> xtanβ – xtan
= h tan
=> x(tanβ – tan
) = h tan
=> x = (h tan2) / (tanβ – tan
)
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