Question
A man whose height is 1.5 metres is standing 24√3 metres away from a light pole. The angle of elevation from his head to the top of the light pole is 30 ° . Find the height of the light pole.
Let AB = height of the man And, CD = Height of the pole And, BD = AE = distance between the man and the pole = 24√3 metres In right triangle AEC; tan30° = CE/AE Or, 1√3 = CE/ (24√3) Or, CE = 24 metres So, height of the pole = CE + ED = CE + AB = 24 + 1.5 = 25.5 metresMore Height and Distance Questions
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