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Let AB = height of the man And, CD = Height of the pole And, BD = AE = distance between the man and the pole = 24√3 metres In right triangle AEC; tan30° = CE/AE Or, 1√3 = CE/ (24√3) Or, CE = 24 metres So, height of the pole = CE + ED = CE + AB = 24 + 1.5 = 25.5 metres
(47.981% of 295) + (24.91% of 245) =?
(1440.13 ÷ 31.77) × (√168.69 + 16) - (24.87% of 719.99) = ?
A man lost one-fourth of his initial amount in the gambling after playing three rounds. The rule of Gambling is that if he wins he will receive Rs. 1000...
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
13³ + 1.3² + 1.03¹ + 1.003 = ?
?2 = 159.97% of 65.004 + 319.98 ÷ 15.99 - 24
What approximate value should come in place of question mark (?) in the following equations?
39.9% of 1720 + 80.2% of 630 = 89.9% of 1280 + ?
2 (1/4)% of 7999.58 + {49.06% of 898.87} + √143.14 – 19.99% of 1499.63 - (52 - 41) = ?
