If in the given figure AD is perpendicular to BC, AC = 26 units, CD = 10 units, BC = 42 units, triangle DAC whose angle is x and angle B = y, then, find the value of 6/cosx -5/cosy +8 tany =?
In ∆ ADC – AD = √(AC)2-DC2 ) AD = √(262-102 ) AD = √(676-100) AD = √576 = 24 AD = 24 Now in ∆ABD AB = √(AD)2+(BD)2 ) AB = √(242+322 AB = √(576+1024) = √1600 AB = 40 NOW- ∴The side opposite to the angle is the hypotenuse, so the base for angle x will be AD. cosx=24/26 cosy=32/40 tany=24/32 6/cosx -5/cosy +8 tany =? =6/(24/26)-5/(32/40)+8×24/32 =26/4 - 25/4 + 24/4 =(50-25)/4 =25/4 6/cosx -5/cosy +8 tany =25/4
Which dynasty of the Delhi Sultanate ruled for the longest period?
Who was known as ‘Andhra-Bhoja’?
Which dynasty is associated with the Gandhara School of Art?
Which battle marked the beginning of British rule in India?
When did the First Battle of Panipat occur?
The original name of Balban was
The most learned medieval Muslim ruler who was well versed in various, branches of learning including astronomy, mathematics and medicine was
The Mongols appeared for the first time on the banks of the Indus during the rule of
The city of Ajmer was founded by
Identify the historical personality from the following clues:
(I) He defeated Mughal forces in the Battle of Wai.
(II) He provided pr...
