From the top of an upright pole 30√3 feet high, the angle of elevation to the top of an upright tower was 60°. If the foot of the pole was 55 feet away from the foot of the tower, what is the height of the tower?
The height of poll AB= 30√3 =AB=DC=30√3 AD=BC=55feet Let ED=x Then Tan60 = ED/AD √3=x/55 X=55√3 Now -the height of the tower CE=ED+DC=55√3+30√3 =85√3feet
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
I. 2y2- 37y + 143 = 0
II. 2x2+ 15x – 143 = 0
I. 2x2 + 12x + 18 = 0
II. 3y2 + 13y + 12 = 0
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
I. 117x² + 250x + 117 = 0
II. 54y² -123y + 65 = 0