Two ships are opposite a lighthouse such that all three of them are collie Zār. The angles of depression of the two ships from the top of the light house 30º and 60º. If the ships are 230 √ 3m apart, then find the height of the light house (in m).
As we know AD/DB=3/1 Then- 4=230√3 DB=1=230√3 /4 Now – Tan 60° =CD/DB √3 =CD /DB CD=√3 ×DB =√3×230√3/4 230×3/4=690/4 =172.5m
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