The height of the tree before it broke =AB+AC trigonometry (tan) = opposite/adjacent): tan 30° = AB/30 Since tan 30° = 1/√3 1 /√3 =AB/30 AB=30/√3 =10√3m AB = 10√3 Cos 30° =BC/AC √3 /2 =30 /AC AC =60 /√3 AC =20√3. Now the height of the tree=AB+AC =10√3 +20√3 =30√3
Statements: L > M > P = N ≤ O ≤ Q, R > S = L
Conclusions:
I. P > S
II. Q ≥ M
III. N < S
Statements: R % B, B & T, T @ E, E % G
Conclusions : I. T $ R II. R @ E III. B @ G
...Statement: N < O; Q ≤ P = O; S > P; R ≥ O
Conclusion:
I. S > R
II. R ≥ S
Statements: O > M = Q > S; M ≥ K > A; Q ≤ O < E
Conclusions: Â Â Â Â Â I. O > SÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. K < OÂ Â Â Â Â Â Â...
Statements: Q © E, S % C, E $ S, C @ AÂ
Conclusions:Â
I. A © CÂ
II. S % AÂ
III. C © Q
Statements: V ≥ O ≥ S = A > J, M < Y = P ≤ O > R
Conclusion:
I. O > M
II. A ≥ M
III. V > RÂ Â
Statements: A > B > C, C < D > E, E = F > G
Conclusion:
I. C = G
II. A > F
Statements: V ≤R = W ≥ Q, U = T ≥ S < X, U < Q
Conclusions: I. V < Q II. Q > X
Statement- 1 - 6#≥9#≥10#≤5#
2 - 7*≤10#˃5*≥6*
Conclusions:
1) 7* > 6*
2) 6* > 7*
3) 6# ≤ 5#<...
Statements:S > T,T ≥ U,U < V
Conclusions: I. T > V II. S > U