Question
A long metallic cable is stretched from a point P on the
ground to the top of a cliff, forming an angle of 30 ° with the horizontal ground. The total length of the cable is 450 √3 meters. Determine the horizontal distance between point P and the base of the cliff.Solution
In the given figure, let 'A' and 'B' represent the foot and the top of the cliff, respectively. In right rPAB, cos30o = (AP/PB) Or, (√3/2) = (AP/450√3) So, PA = (450√3) X (√3/2) = 675 metres Therefore, distance between point 'P' and the foot of the cliff is 675 metres
[(40)2 ÷ 32 × 4] ÷ 50 = ?
30% of 180 + 248 ÷ ? - √256 = 102
((67)32 × (67)-18 / ? = (67)⁸
- What will come in the place of question mark (?) in the given expression?
5555 ÷ 11 ÷ 5 = 100 +? What will come in the place of question mark (?) in the given expression?
642 - 362 = ? X √1225
115 ÷ 23 + 12 × 6 = ? + 16 - 35
2350 – 4830 + 9570 + 3350 – 1720 = ?
(-251 × 21 × -12) ÷ ? = 158.13
(288 ÷ 12 + 15 × 5 + 124) = ?
3.55 + 1.05 + 2.5 × 13 – 12% of 12.5 = ?