Question
A pole 9√3 m high casts a shadow 27 m long on the ground. Find the angle of elevation
If ' θ ' is the angle of elevation then here tan θ = length of Pole/ Shadow = 9√3/27 = 1/√3 = tan 30 or θ = 30°More Height and Distance Questions
- Now a chord of a circle is such that AB = 10 cm. If the diameter of the circle is 20 cm, then the angle subtended by the chord at the center is.
- The angle of elevation of the top of a building from a point on the ground is 30° and moving 40 meters towards the building it becomes 60°. The height of t...
- There is a fire in the building. A man on the top of the building see a Fire brigade van coming towards it. If it takes 8 minutes for the angle of depressi...
- The distance between two parallel poles is 65√3 m. The angle of depression of the top of the second pole when seen from the top of first pole is 30o....
- The length of the shadow of a vertical tower increases by 9 m on horizontal ground when the height of the sun changes from 45° to 30 ° , then find ...
- Find the area of maximum side of square that can be inscribed in a right angled triangle of side 15, 20 and 25 cm.
- Two buildings are collinear with the base of a tower and are at a distance 9m and 16m from the base of the tower. The angles of elevation from these two bu...
- A shadow of a tower standing on level ground is found to be 40√3 meters longer when the Sun's altitude is 30° than when it is 60°. The height of the tower ...
- The angle of depression of a point on the ground as seen from the top of a tower, 25 feet high, is 45°. Find the distance of the point on the ground from t...
- From a watch tower of 150 m height, the angles of depression of two cliffs in a horizontal line through the base of the tower are 45° and 30°. Find the dis...
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
