Question
A man 1.5 m tall is 22.5 m away from a tower 24 m high.
Determine the angle of elevation of the top of the tower from the eye of the observer.Solution
In △ CDE, tan θ = CD/CE = (BD - BC)/CE = (24 - 1.5)/ 22.5 = 22.5/22.5 tan θ = 1 = tan 45 °  θ = 45 °
More Height and Distance Questions
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
(350/?) = 23 + 33
25% of 250 + 32% of 200 = ? ÷ √ 16
? = 20% of 1200 + 256
21% of 400 − 150 = ? − 77
172Â - 92Â + 121 - 74 = ?
24% of 150% of 500 + 140 = ? × 8Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
? = 65% of 40% of (20 × 250) − 200
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