Question
There are two houses of the same height on both sides of
a 15-meter wide road. From a point on the road, elevation angles of the houses are 30° and 60° respectively. Find the height of the houses.Solution
Let y be the height of the houses, here AB = CD = y meter. Let x be the distance between the point on the road and the house making an elevation angle of 60°, here BE = x meter. Then, (15 - x) is the distance between the point on the road from the house making an elevation angle 30°, here DE = (15 - x) meter. Now, tan 60° = AB/BE ⇒ √3 = y/x ⇒ x = y/√3  ...(i) Also, tan 30° = CD/DE ⇒ 1/√3 = y/(15 - x) ⇒ √3y = 15 - x ⇒ √3y = 15 - y/√3  [from equation i] ⇒ 3y = 15√3 - y ⇒ 4y = 15√3 ⇒ y = 15√3/4 ≈ 6.5 meter
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)     Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
236.23 - 653.23 + 696.23 = ?
Simplify the following expressions and choose the correct option.
40% of 360 + 25% of 248 - 30
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7The value of 97 × 103 is _________.
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
? = 20% of 1200 + 256
55.55% of 30000 – 1111 = ? × 1111
30% of 60% of 1800 + 13 × 14 = (? ÷ 75) × 5