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The annual income of Rehan is Rs. 672000. Monthly income of Rehan = 672000/12= Rs. 56000 He spent 28% of his monthly income on rent. ‘z’% of the remaining monthly income was spent on food by him. If (z-15)% of the remaining monthly income was spent on travelling and remaining money was saved which is equal to Rs. 4032. 56000 of (100-28)% of (100-z)% of (100-(z-15))% = 4032 56000 of 72% of (100-z)% of (100-z+15)% = 4032 56 x 72 x (100-z) x (115-z) = 4032000 (100-z) x (115-z) = 1000 Z2 − 215z + 10500 = 0 Z2 − (140+75)z + 10500 = 0 Z2 − 140z - 75z + 10500 = 0 z(z − 140) - 75(z − 140) = 0 (z − 140) (z − 75) = 0 z = 140, 75 There are two possible values of ‘z’. But as per the options the value of z will be 75.
I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 21x + 110 = 0
Equation 2: y² - 23y + 132 = 0
I. 7p + 8q = 80
II. 9p – 5q = 57
I. 2 x² - 15 + 18 = 0
II. x²- 3 + 2 = 0
...I. 5x2 – 18x + 16 = 0
II. 3y2 – 35y - 52 = 0
What are the coordinates of the point which divides the line joining (-1, 7) and (4, 3) in the ratio 2:3?
I. 35x² - 46x – 16 = 0
II. 35y² - 116y + 96 = 0
I. 6x² - 13 x + 6 = 0
II. 15 y² + 11 y - 12 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 33x² - 186x + 240 = 0
Equation 2: 35y² - 200y + ...
I: x2 - 33x + 242 = 0
II: y2 - 4y - 77 = 0