The sum of the income of Raj and Roni is Rs. 168000. A spends 50% of his income and B spends 75% of his income in such a way that B’s saving is Rs. 9000 less than A. If the income of C is 10% more than the average saving of A and B. Find the sum of saving of B and C if saving of C is 30%.
Let the income of B be Rs. X So, the salary of A will be Rs (168000-x) Saving of A = Rs (168000-x) × 0.5 Saving of B = Rs 0.25x As per the question 0.5×(168000-x) = 0.25x+9000 84000-0.5x = 0.25x+9000 0.75x = 75000 X= Rs 100000 Saving of A and B is Rs 34000 and Rs 25000 respectively Income of C = (1+(10/100)) ×((34000+25000)/2) = (110/100)×(29500) = Rs 32450 Saving of C = (30/100) ×(32450) = Rs 9735 Sum of the saving of B and C = Rs. 9735 + Rs 25000 = Rs 34735
9999² + 1111² =?
641.5 + 72 × 8 = ? × 4
72 + 122 - 25% of 600 = ?
∛157464 =?
6 0 - 20 [8 + 12 {8-8 (20-12)+20}-40] ÷ 16 =?
(49 x ?) / 3.5 + 389 = 627
2850 ÷ 2.5 - ? × 42 = 300
135.37 – 50.24 + 629.09 – 199.50 = ? – 214.68 + 42.65
1885 ÷ 64.98 + 7.29 + ? = 69.09
? ÷ 8 = 2048 ÷ 64