If x-y√3 = 15 and √3 x+y = 23
Find the angle between both the lines when they intersect each other?
x-y√3 = 15 y= x/√3- 15/√3 Slope m₁ = 1/√3 Now, √3 x+y=23 y= -√3 x+23 Slope m₂ = -√3 If two lines intersect each other at some point, then slope m₁ and Slope m₂ tanθ= |(m1- m2)/(1+ m1 m2 )| tanθ= |(1/√3- √3)/(1+(-√3 × 1/√3))| tanθ= |(1-3)/0| = ∞ tan90˚ = ∞ θ = 90˚
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