Using formula Area of triangle = 1/2 x base x height and Area of circle = πr2, Let the corresponding altitude of the triangle = a cm. According to the question, Area of the triangle = Area of the circle ⇒ 1a/2 x 6 = π x 6 x 6 ⇒a = 2 x 6 π ⇒a = 12 π cm
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