Question
If the areas of three adjacent faces of a rectangular
box which meet in a corner are 12cm2, 15cm2 and 20cm2 respectively. Then the volume of the box isSolution
let length , breadth , height be l, b, h respectively l × b = 12 ------------- eq 1 b × h = 15---------------eq2 h × l = 20----------------eq3 multiply eq 1 by eq2 and dividing eq3 we get (l×b×b×h)/ h×l = b2 = (12×15)/20 b = 3 from eq 1 we get l = 4 from eq 2 we get h = 5 volume of the cuboid = l × b × h = 3 × 4 × 5 = 60 cm3 Â
- The side of a square is 50% less than the length of a rectangle with area 2880 cm² and breadth 60 cm. What is the perimeter of the square?
(4x³y – 6x2y2 + 4xy3 y4) can be expressed as:
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