Question
Four circles of equal radii are described about the four
corners of a square so that each touches two of the other circles. If each side of the square is 140 cm then area of the space enclosed between the circumference of the circle is (take π = 22/7)Solution
Side of the square a = 140 cm Radius of the circle r = 140/2 = 70 cm Area of 4 quadrant = area of 1 circle As we know, Area of the square = a2 Area of the circle = πr2 Area of the space enclosed between the circumference of the circle = a2 – πr2 ⇒ 140 × 140 – (22/7) × 70 × 70 ⇒ 19600 – 15400 ⇒ 4200 cm^2
√10404 + √9604 - ∛1728 - ∛42875 = ?
1299.999 ÷ 325.018 × 24.996 = ?
24% of 400 × 16% of ? = 384
Determine the simplified value of the given mathematical expression.
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?Â
82% of 400 + √(?) = 130% of 600 - 85% of 400
192.251 + 326.233 + 125.021 + 19.273 = ?
45% of 360 - 160 + ? = √324
(160 × 12 - 13 × 20)/(120 × 2 + 2 × 35 + 2 × 11) = ?
