The lateral surface area of frustum of a right circular cone, if the area of its base is and the diameter of circular upper surface is 4 cm and slant height 6 cm, will be
24% of 150% of 500 + 140 = ? × 8
23 × 20 + ? = 182 + 92 + 82
(180 ÷ 22 ) ÷ (60% of 30) = (? ÷ 2)
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
1672 ÷ 19 = ?% of 220
What should come in place of the question mark (?) in the following question?
2 – [6 – {3 + (–4 + 5 + 1) × 8} + 12] = ?
360 ÷ 4 ÷ 3 = 150 – ?
{5% of (20 × 25) + 6% of (30 ×35)} ÷ 11 = ?
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
