Question
If the radius of the right circular cylinder is doubled
and the height is halved, then the ratio of the new volume and the previous volume of the cylinder is?Solution
let the height of cylinder = h radius of cylinder = r volume of cylinder = πr2h when radius = 2r & height = h/2 New volume of cylinder = π4r2 (h/2) Required ratio = π4r2 (h/2) : πr2h = 2:1
β256 * 3 β 15% of 300 + ? = 150% of 160
What value should come in the place of (?) in the following questions.
336 Γ· 6 Γ· β16 * ? = 1400 Γ· 4
52% of 400 + √(?) = 60% of 600 - 25% of 400
30 of 20 - 40 + 182 - 23 Γ ? = 83Β
60 = (? x 10 + 250)/5

25% of 300 + √(?) = 35% of 600 - 15% of 300
x= β(4 Γ β(16 Γ β(4 Γ β(16 Γβ¦β¦ β)) ) )Β
32% of 4080 + 24% of 455 = x% of 4000
(47.5 ÷ 9.5) × (78.5 ÷ 15.7) + 475 = ? + 15% of 150