The population of a town is 64000. It increased by 10% during the first year. During the second year, it decreased by 25% and increased by 5% during the third year. What is the population after 3 years?
Population after 3 years = 64000 x {(100+10)/100} x {(100-25)/100} x {(100+5)/100} = 64000 x (110/100) x (75/100) x (105/100) = 55440
148, ‘?’ , 15 4 , 17 8 , 23 8 , 35 8 , 56 8
If  3  12  108  x   43200
Then, 47% of (x + 72)= ?
8      24       48      144      ?     864
...Find the value of c.
-3Â Â Â Â Â -2Â Â Â Â -12Â Â Â Â -9Â Â Â Â -100Â Â Â Â Â Â Â -375
 31    a     Â...
4 6 ? 31 119 601
...6 , 21, 116, ?, 4674, 33593
6 3.5 2.5 ? 8.5 23.75
...1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
52 25 27 ? 208 1648
...7Â Â Â Â Â Â Â Â Â Â Â 26Â Â Â Â Â Â Â Â Â Â Â Â Â Â 238Â Â Â Â Â Â Â Â Â Â Â Â Â Â 962Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 8522Â Â Â Â Â Â Â Â Â Â Â Â Â ...
