Get Started with ixamBee
Start learning 50% faster. Sign in now
Sum of first 10 terms is equal to sum of first 12 terms. Sum of first 12 terms = Sum of first 10 terms + 11th term + 12th term 11th term + 12thterm = 0 Let 11thterm = k, common ratio = r 12thterm will be = kr k + kr = 0 k (1 + r) = 0 r = -1 as k cannot be zero Common ratio = -1 Now, sum of 15 terms = a(r - 1)/(r - 1) = 31 ⇒ a(-1 -1)/(-1 -1) = 31 ⇒ a = 31 ∴ Third term = ar = 31 × (-1) = 31
385! In the trailing Zeros, let us know.
There are three numbers 'u', 'v' and 'w' (u < v < w) such that 'v' is equal to the average of 'u' and 'w'. 80% of 'w' is equal to 'u' and the difference...
What is the remainder when (x²⁷ + 51) is divided by (x + 1)?
The number 611611611611611611611 is
Find the sum of all those 3-digit numbers which when divided by 10 leave a remainder of 5.
A two-digit number is such that the sum of its digits is 10. If 36 is added to the number, the digits interchange their places. Find the number.
What is the average of all the prime numbers which are less than 35?
Five times a positive integer is 3 less than twice its square. Find the integer.
What is the fourth proportional of √20, √30, and √18?
The sum of the squares of three natural numbers is 342. These numbers are in the ratio of 3:5:2. Determine the difference between the largest and smalle...
