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Total weight of friends A, B, C, D and E = 5(x+8) kg So, Total weight of A, B and D = 5(x+8) - 2(x-8) = (3x+56) kg Weight of F = [(x+8-7)×6] - [5(x+8)] => F = (x-34) kg According to the question, => (3x+56) + (x-34) = 92.5 × 4 => 4x + 22 = 370 => 4x = 348 => x = 87
1360 ÷ 8 + 490 ÷ √49 + ? = 150 × 2
√(2670+ √(1141+ √(260- √(1251- √(637+ √1521) ) ) ) ) =?
√256 * 3 – 15% of 300 + ? = 150% of 160
20 * 8 + 40% of 100 + 60% of 150 = ?
14 × 6 + 9 × 11 = (82 – 3) × ?
(43)² - (28)² + (32)² = ?% of 2500
? = √2704 ÷ (25% of 104) + 73
Simplify the given expression:-