The length of sides of a square is twice the radius of a circle and perimeter of a rectangle is half the perimeter of the square. If the sum of length and breadth of rectangle is 24 cm, then find the area of the circle (in cm2). [Take π = 2]
Let the length of a square be ‘a’. And the radius of a circle be ‘r’. Now, a = 2r ----- (i) Perimeter of the rectangle = 1/2 × 4a = 2a => 2(l + b) = 2a => 2 × 24 = 2a => a = 24 cm Putting value of ‘a’ in (i) we get, Radius = r = 24/2 = 12 cm Area of the circle = πr2= 2 × 12 × 12 = 288 cm2.
96.03% of √225.02 × 14.98 = ? + 19.98
47.87% of 749.76 + 35.11% of 399.76 = √? + 23.15 × 20.87
2720.03 ÷ 79.98 x 39.9 = ? + 40.32
33.33% of 110.99 = 19.98% × 244.97 - √?
3.55% of 8120 – 66.66% of 540 = ? – 28% of 5500
1359.98 ÷ 30.48 × 15.12 = ? × 4.16
(0.89 3 + 1.64 3 +2.76 3 ) ÷ 5.89 = ?
12.06 × 19.02 + 12.94 × 14.87 + 152.09 = ?% of 498.98
(?)2 + 9.113 = 31.92 – 39.03
