<p>&lt;p&gt;The area of four walls of a room is 120 cm&lt;sup&gt;2&lt;/sup&gt;. If the length and breadth of the room were equal and the height of the room is 5 cm, then what is the area of the floor?&lt;/p&gt;</p>

Solution

<p>&lt;p&gt;According to question, &amp;nbsp;&lt;/p&gt; &lt;p&gt;&amp;nbsp; =&amp;gt; l = b &amp;nbsp; Area of the wall = 2(l + b) h &amp;nbsp;&lt;/p&gt; &lt;p&gt;=&amp;gt; 120 = 2(l + l) &amp;times; 5&amp;nbsp; &amp;nbsp;&lt;/p&gt; &lt;p&gt;=&amp;gt; 120 = 4 &amp;times; l &amp;times; 5 &amp;nbsp;&lt;/p&gt; &lt;p&gt;=&amp;gt; l = 120/20 = 6 cm&lt;/p&gt; &lt;p&gt;&amp;nbsp; Area of the floor = l &amp;times; b = 6 &amp;times; 6 = 36 cm&lt;sup&gt;2&lt;/sup&gt;&amp;nbsp;&lt;/p&gt;</p>