Question
On a rectangular wall of length 28 metres and height 23
metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 8 metres and length of altitude of the triangle is 5 metres, then excluding the window, what is the surface area of the wall?Solution
Surface area of the entire wall = length × height = 28 × 23 = 644 m2 Surface area of the window = sum of surface area of the square part + surface area of the triangular part => 82 + (1/2) × 8 × 5 => 64 + 20 = 84 m2 Required surface area = 644 – 84 = 560 m2
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