New RBI Grade B 2025 Notification will come Soon! Enroll Here

    Question

    The angle of elevation of the top of a tower from a

    point on ground which is 30 mtrs. away from the foot of the tower is 30°. Height of the tower is: 1.10/ √3 mtrs 2.10 × √3 mtrs 3.100 mtrs 4.20meter.
    A 2 Correct Answer Incorrect Answer
    B 3 Correct Answer Incorrect Answer
    C 4 Correct Answer Incorrect Answer
    D 1 Correct Answer Incorrect Answer

    Solution

    Let us consider the height of the tower as AB, the distance between the foot of the tower to the point on the ground as BC. In ΔABC, trigonometric ratio involving AB, BC and ∠C is tan θ. tan C = AB/BC tan 30° = AB/30 1/√3 = AB/30 AB = 30/√3 = (30 × √3) / (√3 × √3) = (30√3)/3 = 10√3 Height of tower AB = 10√3 m.

    Practice Next

    Relevant for Exams: