Question
A metallic sphere of radius 4.2 cms. Is melted and
recast into the shape of a cylinder of radius 6 cms. Height of the resultant cylinder would be:Solution
As a metallic sphere is melted and recast into the shape of a cylinder, their volume must be the same. Volume of the sphere = Volume of the cylinder Let us find the volume of the sphere and cylinder by using formulae; Volume of the sphere = 4/3πr3 where r is the radius of the sphere Volume of the cylinder = πr2h where r and h are radius and height of the cylinder respectively Radius of the sphere, r₁ = 4.2 cm Radius of the cylinder, r₂ = 6 cm Let the height of the cylinder be h. Volume of sphere = Volume of cylinder 4/3πr₁3 = πr₂2h (4/3)r₁3 = r₂2h h = 4r₁3 / 3r₂2 = (4 × 4.2 cm × 4.2 cm × 4.2 cm) / (3 × 6 cm × 6 cm) = 2.744 cm Hence, the height of the cylinder so formed will be 2.744 cm.
22 + 60 × 3 ÷ 12 = ?
(6 × √361) × 2.5 = ? + 125
40% of (362 ÷ 0.05) = ?
(122 - 82 ) of 52 + 52 = ?2
225÷ 25 x 21 - 30 = ? + √2209 - √7744
√ [? x 11 + (√ 1296)] = 16
`2(1/3)` + `4(1/4)` + `4(2/3)` + `8(7/6)` + ? = `4(3/5)xx4(1/2)`
...- What will come in place of the question mark (?) in the following questions?
120÷(5×2)+8=? What value should come in place of the question mark (?) in the following question?
45 × 2 + 180 ÷ 6 − 12 = ?
Find the value of ?
{[(864 ÷ 18) ÷ 8] ÷ 3} + 11² – 2³ = ?