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Let the perimeter of the square and circumference of the circle be ‘9x’ cm and ‘11x’ cm, respectively. Area of square = a2 (Where ‘a’ is the side of the square) ATQ; 81 = a2 Or, a = 9 cm So, perimeter of the square = 9 × 4 = 36 cm So, circumference of circle = 36 × (11x/9x) = 44 cm Circumference of circle = 2πr (Where ‘r’ is the radius) So, 44 = 2 × (22/7) × r Or, r = 7 cm Therefore, radius of the circle is 7 cm.
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the question...
4 8 12 48 ? 432
...5 14 56 220 1125 6786
...3601 3602 1803 604 154 36
...? 12 24 44 74 116
...18 434 642 746 798 ?
...If 6 4 x 5.75 9,
Then, (x²-1) = ?
...2, A, 9, B, 6, C, 13, D, ?
1 5 36 343 ? 59049
...12, 16, 25, 41, 66, ?
